CHEMISTRY PRACTICAL QUESTIONS AND ANSWERS NOW READY
CHEMISTRY PRACTICAL COMPLETE QUESTIONS & ANSWERS NOW AVAILABLE. subscribe for the expo before its too late To subscribe, call/WhatsApp 08170610547 Subscribers will always get it earlier than it's being posted here. (1) Volume of Pipette used 25.0cm^3 Titration | Rough | First | Second | Third Final burette reading (cm^3) | 22.50 | 45.10 | 32.65 | 27.60 Intial burette reading (cm^3) | 0.00 | 22.50 | 10.00 | 5.00 Volume of A used (cm^3) | 22.50 | 22.60 | 22.65 | 22.70 (1a) Average volume of A = 22.60 + 22.65 + 22.70/3 = 22.65cm^3 (1bi) GIVEN: CB = 0.10moldm^-3 VB = 25cm^3 CA = ? VA = 22.65cm^3 Equation of reaction: H2C2O4(aq) + 2NaOH(aq) ====> Na2C2O4(aq) + 2H2O(l) hence, nA = 1 Nb = 2 Using CAVA /CBVB = nA/nB CA = CBVBnA/VanB =0.10 × 25 × 1/22.65 × 2 CA = 0.055 moldm^-3 Concentration of A in moldm^-3 = 0.055 (bii) Using: gram concentration = molar concentration × molar mass conc. Of A in gdm^-3 = 0.055 × [(1 × 2) + (12 × 2) + (16