MATHEMATICS WAEC GCE 2017 QUESTIONS AND ANSWERS NOW READY

September 08, 2017

Waec Gce 2017 Mathematics QUESTION AND ANSWERS NOW 100% AVAILABLE WITH US.IT WILL DROP BY 3AM ON THE 9TH OF SEPTEMBER.SUBSCRIBE AND GET IT..TO SUBSCRIBE,CALL/WHATSAPP MR PORTAL ON *090............*

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11)
A={4,5,6,7,8,9,10,11,12}
B={10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}
M={4,8,12,11,6,20,24,28}
a)prob (A)=3/7
b)prob( B)=7-4/7=3/7
c)prob(AuB)=n(AuB)/n(m)
but (AuB)={4,8,12,11,6,20,24,}
prob(AuB)=6/7
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9a) Diagram

(9b)
a= 360-330{ =030 degree
b=a=030degree{alternate angles}
Φ = 090degree+030degre
= 120degree
(i) find distance AC wing.
|AC|²= |BC|²+|AB|²–2|AB||BC|Costita
|AC|²= 300²+100²–2(300)(100)Cos120degree
= 90000+10000–60000×(-0.5)
=100,000+30,000
= 130,000
|AC| = √130,000 = 360.555KM
=360.56Km(2d.p)

(ii)
find β, applying the first rule
300/Sinβ = 360.56/Sin120
Sinβ = 300sin120/360.56 = 259.81/360.56
= 0.7206
β = sin inverse(0.7206)
= 46degree
Therefore the bearing of the plane from A
=330–046
=284degrees.

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